How do you get sec 30? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Alan P. Sep 8, 2015 #sec(30^@) = (2sqrt(3))/3# Explanation: #sec = 1/cos# #30^@# is one of the "standard" angles #cos(30^@) = ("adjacent")/("hypotenuse") = sqrt(3)/2# #rArr sec(30^@) = 2/sqrt(3) = (2sqrt(3))/3# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 2944 views around the world You can reuse this answer Creative Commons License