# How do you graph 10x>=10/3# on the coordinate plane?

Aug 22, 2017

See a solution process below:

#### Explanation:

First, we can solve for $x$ by multiplying each side of the inequality by $\textcolor{red}{\frac{1}{10}}$ which will also keep the inequality balanced:

$\textcolor{red}{\frac{1}{10}} \times 10 x \ge \textcolor{red}{\frac{1}{10}} \times \frac{10}{3}$

$\frac{10}{10} x \ge \textcolor{red}{\frac{1}{\textcolor{b l a c k}{\cancel{\textcolor{red}{10}}}}} \times \frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{10}}}}{3}$

$1 x \ge \frac{1}{3}$

$x \ge \frac{1}{3}$

To graph this inequality we draw a vertical line at the $\frac{1}{3}$ point on the $x$-axis.

The line will be a solid line because the inequality operator has a "or equal to" clause.

We wil shade to the right of the line because the inequality operator has a "greater than" clause:

graph{x>=1/3 [-8, 8, -4, 4]}