How do you graph #-2x-3y=-12# using intercepts?

1 Answer
Aug 17, 2017

Answer:

See a solution process below:

Explanation:

x-intercept

To find the #x#-intercept set #y# to #0# and solve for #x#:

#-2x - 3y = -12# becomes:

#-2x - (3 xx 0) = -12#

#-2x - 0 = -12#

#-2x = -12#

#(-2x)/color(red)(-2) = (-12)/color(red)(-2)#

#x = 6# or #(6, 0)#

y-intercept

To find the #y#-intercept set #x# to #0# and solve for #y#:

#-2x - 3y = -12# becomes:

#(-2 xx 0) - 3y = -12#

#0 - 3y = -12#

#-3y = -12#

#(-3y)/color(red)(-3) = (-12)/color(red)(-3)#

#y = 4# or #(0, 4)#

Next, plot these two points.

graph{((x-6)^2+y^2-0.025)(x^2+(y-4)^2-0.025)=0}

Now, draw a line through the two points to graph the line of the equation:

graph{(-2x-3y+12)((x-6)^2+y^2-0.025)(x^2+(y-4)^2-0.025)=0}