Question

How do you graph `2x+y-4=0` by plotting points?

Answer 1

`"see explanation"`

Explanation:

`"one way is to find the intercepts, that is where the graph"`
`"crosses the x and y axes"`

`• " let x = 0, in the equation for y-intercept"`

`• " let y = 0, in the equation for x-intercept"`

`x=0rArry-4=0rArry=4larrcolor(red)"y-intercept"`

`y=0rArr2x-4=0rArrx=2larrcolor(red)"x-intercept"`

`"Plot the points "(0,4)" and "(2,0)`

`"Draw a straight line through them for graph"`
graph{(y+2x-4)((x-0)^2+(y-4)^2-0.04)((x-2)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}