# How do you graph #3 < -2y+6x#?

##### 1 Answer

Jul 4, 2015

Graph

#### Explanation:

Standard form of a linear function in 2 variable:

-2y + 6x - 3 > 0

First, graph Line: - 2y + 6x - 3 = 0 by its intercepts.

Make x = 0 -> y = 1/2. Make y = 0 -> x = - 3/2.

To find the solution set area, use origin O as test point. Substitute x = 0 and y = 0 into the inequality, we get -3 > 0. Not true. Then, the solution set area doesn't contain the origin O. The solution set is the area below the line. Color this answer.

Graph graph{- 2y + 6x - 3 = 0 [-10, 10, -5, 5]}