# How do you graph 3q+7>=13?

First graph $y = 3 q + 7$ by choosing two conventient $q$'s and calculating the corresponding $y$'s ($q = 0$ is allways a good choice). Then draw a line through them. Also draw the horizontal line at $y = 13$. Everywhere the first line is on or above the $13$-mark is a solution (answer: $q \ge 2$)