# How do you graph  3x - 4y = -8?

See below:

#### Explanation:

For graphing, I like using the slope-intercept form, where the general form is

$y = m x + b$, where $m$ is the slope and $b$ is the $y$-intercept.

To get there, solve for $y$:

$3 x - 4 y = - 8$

$- 4 y = - 3 x - 8$

$y = \frac{3}{4} x + 2$

We now have a form where we can pick out the $y$-intercept (the point $\left(0 , 2\right)$. We can use the slope to find another point to plot.

$\text{Slope"="rise"/"run}$ and so we can add 3 to the $y$ value for every 4 we add to the $x$ value:

$\left(0 + 4 , 2 + 3\right) = \left(4 , 5\right)$

We now have to points so we can graph the line:

graph{((x-0)^2+(y-2)^2-.1)((x-4)^2+(y-5)^2-.1)(3x-4y+8)=0[-15,15,-7,7]}