How do you graph # 3x - 4y = -8#?

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Answer 1 · 2018-01-19T09:50:50

See below:

For graphing, I like using the slope-intercept form, where the general form is

#y=mx+b#, where #m# is the slope and #b# is the #y#-intercept.

To get there, solve for #y#:

#3x-4y=-8#

#-4y=-3x-8#

#y=3/4x+2#

We now have a form where we can pick out the #y#-intercept (the point #(0,2)#. We can use the slope to find another point to plot.

#"Slope"="rise"/"run"# and so we can add 3 to the #y# value for every 4 we add to the #x# value:

#(0+4,2+3)=(4,5)#

We now have to points so we can graph the line:

graph{((x-0)^2+(y-2)^2-.1)((x-4)^2+(y-5)^2-.1)(3x-4y+8)=0[-15,15,-7,7]}