How do you graph # 3x - 4y = -8#?
1 Answer
Jan 19, 2018
See below:
Explanation:
For graphing, I like using the slope-intercept form, where the general form is
To get there, solve for
We now have a form where we can pick out the
We now have to points so we can graph the line:
graph{((x-0)^2+(y-2)^2-.1)((x-4)^2+(y-5)^2-.1)(3x-4y+8)=0[-15,15,-7,7]}