# How do you graph 3x+5y=-15 using intercepts?

Mar 1, 2017

Our intercepts are (-5,0) and (0,-3)

#### Explanation:

Solve for y:

$5 y = - 15 - 3 x$

$y = - 3 - \left(\frac{3}{5}\right) x$

Plug in 0 for x:

$y = - 3 - \left(\frac{3}{5}\right) \left(0\right) = - 3$

Plug in 0 for y:

$0 = - 3 - \left(\frac{3}{5}\right) x$

Solve for x:

$3 = - \left(\frac{3}{5}\right) x$

$- 5 = x$

So our intercepts are (-5,0) and (0,-3)

Now we can graph these points and connect them with a line.

graph{-3-(3/5)x [-10, 10, -5, 5]}