How do you graph 3x-6y=12 using the intercepts?

Feb 4, 2017

I tried this:

Explanation:

We find the coordinates of the two intercepts by seting:

$x = 0$ in our equation.
We then get: $3 \cdot 0 - 6 y = 12$
and: $y = - \frac{12}{6} = - 2$

$y = 0$ in our equation.
We then get: $3 x - 6 \cdot 0 = 12$
and: $x = \frac{12}{3} = 4$

So our intercepts have coordinates:
$\left(0 , - 2\right)$
$\left(4 , 0\right)$

These two points are enough to plot the straight line described by our equation: