How do you graph #3x+y= -2#?

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Answer 1 · 2018-06-15T20:26:56

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#(3 * 0) + y = -2#

#0 + y = -2#

#y = -2# or #(0, -2)#

Second Point: For #y = 1#

#3x + 1 = -2#

#3x + 1 - color(red)(1) = -2 - color(red)(1)#

#3x + 0 = -3#

#3x = -3#

#(3x)/color(red)(3) = -3/color(red)(3)#

#x = -1# or #(-1, 1)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+2)^2-0.035)((x+1)^2+(y-1)^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(3x + y + 2)(x^2+(y+2)^2-0.035)((x+1)^2+(y-1)^2-0.035)=0 [-10, 10, -5, 5]}