How do you graph 3x+y<5?

Jul 5, 2015

Graph: 3x + y < 5

Explanation:

Standard form: y + 3x - 5 < 0 (1). Solving inequality by graphing.

First, graph the Line: y + 3x - 5 = 0 by its intercepts.
Make x = 0 -> y = 5; Make y = 0 -> $x = \frac{5}{3}$.
Next, find the solution set area. Use the origin O as test point. Substitute x = 0 and y = 0 into the inequality (1). We get - 5 < 0. True. Then, O is located on the solution set area. Color or shade it.
graph{y + 3x - 5 = 0 [-10, 10, -5, 5]}