Question

How do you graph `4x-3y=20` using the intercepts?

Answer 1

Please see below.

Explanation:

First find the `x`-intercept by putting `y=0` i.e. `4x=20` or `x=5`, which gives us point `(5,0)`

then find `y`-intercept by putting `x=0` i.e. `-3y=20` or `y=-20/3=-6 2/3`, giving us another point `(0,-6 2/3)`.

Joining two points gives us the graph of `4x-3y=20`, as shown below

graph{(4x-3y-20)(x^2+(y+20/3)^2-0.03)((x-5)^2+y^2-0.03)=0 [-8.33, 11.67, -7.72, 2.28]}