How do you graph #4x-3y=20# using the intercepts?

1 Answer
Jul 1, 2018

Answer:

Please see below.

Explanation:

First find the #x#-intercept by putting #y=0# i.e. #4x=20# or #x=5#, which gives us point #(5,0)#

then find #y#-intercept by putting #x=0# i.e. #-3y=20# or #y=-20/3=-6 2/3#, giving us another point #(0,-6 2/3)#.

Joining two points gives us the graph of #4x-3y=20#, as shown below

graph{(4x-3y-20)(x^2+(y+20/3)^2-0.03)((x-5)^2+y^2-0.03)=0 [-8.33, 11.67, -7.72, 2.28]}