# How do you graph #6x-4y=16#?

##### 1 Answer

Aug 31, 2017

See a solution process below:

#### Explanation:

First, solve for two points which solve the equation and plot these points:

**First Point:**

For

**Second Point:**

For

We can next graph the two points on the coordinate plane:

graph{(x^2+(y+4)^2-0.08)((x-2)^2+(y+1)^2-0.08)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(6x-4y-16)(x^2+(y+4)^2-0.08)((x-2)^2+(y+1)^2-0.08)=0 [-20, 20, -10, 10]}