How do you graph  -7y + 2x + 14 using intercepts?

Jul 18, 2017

The equation given is a line. $- 7 y + 2 x + 14 = 0$

Explanation:

We put values for $x$ and get values out for $y$ or vise versa

So we find two point from which the line goes through

Let's start with $x = 0$

$- 7 y + 2 x + 14 = 0 \implies - 7 y + 14 = 0 \implies y = 2$

so the first point is ${A}_{1} \left(0 , 2\right)$

Now let's pu $y = 0$

$- 7 y + 2 x + 14 = 0 \implies 2 x + 14 = 0 \implies x = - 7$

So the second point is ${A}_{2} \left(- 7 , 0\right)$

The graph is a line that goes through ${A}_{1}$ and ${A}_{2}$
graph{-7y+2x+14=0 [-10, 10, -5, 5]}