How do you graph 8y> -4 on the coordinate plane?

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Feb 9, 2018

See a solution process below:

Explanation:

Divide each side of the inequality by $\textcolor{red}{8}$ to solve for $y$ while keeping the inequality balanced:

$\frac{8 y}{\textcolor{red}{8}} > - \frac{4}{\textcolor{red}{8}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{8}}} y}{\cancel{\textcolor{red}{8}}} > - \frac{1}{2}$

$y > - \frac{1}{2}$

To graph this we will draw a horizontal line at $- \frac{1}{2}$ on the vertical axis.

The line will be a dashed line because the inequality operator does not contain an "or equal to" clause.

We will shade above line because the inequality operator is a "greater than" operator:

graph{y > -1/2 [-4, 4, -2, 2]}

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