How do you graph and find the intercepts for #y = -2.5#?

1 Answer
Mar 29, 2018

Answer:

See a solution process below:

Explanation:

This equation shows for each and every value of #x#; #y# has the same value of #-2.5#. We can graph this equation as:

graph{(0.0000000002x+y+2.5)=0 [-10, 10, -5, 5]}

As you can see from the graph, this is a horizontal line.

The #y#-intercept is at #(0, -2.5)#

graph{(0.0000000002x+y+2.5)(x^2+(y+2.5)^2-0.035) = 0 [-10, 10, -5, 5]}

Because this is a horizontal line there is no #x#-intercept.