How do you graph and label the vertex and axis of symmetry #y=1/2x^2+4x+10#?

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Answer 1 · 2017-11-29T13:14:41

Refer to the graph available with this answer.

We have the quadratic equation

#y = (1/2)x^2 + 4x +10#

Axis of Symmetry is given by #(-b)/(2a)#

So, for our quadratic, Axis of Symmetry = #(-4)/((2*(1/2))#,
which gives us #(-4)#

Substitute this value of Axis of Symmetry in our original equation to obtain the Vertex.

#y = (1/2)(-4)^2 + 4(-4) + 10#

#y = (1/2)16 -16 + 10#

#y = 2#

So, our Vertex is at #(-4, 2)#

Refer to the labeled graph attached with Vertex and Axis of Symmetry identified.
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