How do you graph f(x)=1/4x^2-2x-12 and identify the x intercepts, vertex?
1 Answer
Feb 2, 2018
Refer Explanation section.
Explanation:
Given -
y=1/2 x^2-2x-12
Vertex -
x-coordinate
(-b)/(2a)=(-(-2))/(2 xx0.5)=2/1=2
Y coordinate
At
y=1/2(2)^2-2(2)-12=4/2-4-12=2-4-12=-14
Vertex
Take a few points on either side of
Plot the points and join with a smooth curve.
Its two x-intercepts are given in a separate graph