How do you graph f(x)=1/4x^2-2x-12 and identify the x intercepts, vertex?

1 Answer
Feb 2, 2018

Refer Explanation section.

Explanation:

Given -

y=1/2 x^2-2x-12

Vertex -
x-coordinate

(-b)/(2a)=(-(-2))/(2 xx0.5)=2/1=2

Y coordinate
At x=2

y=1/2(2)^2-2(2)-12=4/2-4-12=2-4-12=-14

Vertex (2,-14)

Take a few points on either side of x=2. Find the corresponding y values. Tabulate them.
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Plot the points and join with a smooth curve.

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Its two x-interceptsenter image source here are given in a separate graph