# How do you graph #f(x)= 2/3(x-3)^2 - 6#?

##### 1 Answer

Plot the vertex, the intercepts (and possibly a few other points) then connect the points with a smooth curve.

#### Explanation:

so as one of our points we have the vertex

The

giving us another point:

The x-intercepts occur where

Unfortunately this only gives us 1 more point (we already had

We could evaluate

graph{2/3(x-3)^2-6 [-4.39, 13.39, -6.404, 2.485]}