# How do you graph f(x)=abs(3x-2)?

$\left\mid 3 x - 2 \right\mid \ge 0$ and
$\left\mid 3 x - 2 \right\mid = 0$ if $\left(3 x - 2\right) = 0$, that is when $x = \frac{2}{3}$
The graph forms a 'V' shape with the sides having slopes $\pm 3$ and vertex at $\left(\frac{2}{3} , 0\right)$
It intercepts the $y$-axis when $x = 0$, giving $f \left(0\right) = \left\mid 0 - 2 \right\mid = 2$,
that is at the point $\left(0 , 2\right)$.