Question

How do you graph `f(x)=abs(3x-2)`?

Answer 1

`abs(3x-2) >= 0` and
`abs(3x-2)=0` if `(3x-2)=0`, that is when `x=2/3`

The graph forms a 'V' shape with the sides having slopes `+-3` and vertex at `(2/3, 0)`

It intercepts the `y`-axis when `x=0`, giving `f(0) = abs(0-2) = 2`,
that is at the point `(0, 2)`.

graph{abs(3x-2) [-10, 10, -5, 5]}