How do you graph f(x)=ln (x-1)+2?

Feb 14, 2017

The standard graph of $\ln x$ shifted +1 unit on the x axis and +2 units on the y axis.

Explanation:

$f \left(x\right) = \ln \left(x - 1\right) + 2$

If $x ' = x - 1 \to x = x ' + 1$

Then: $f \left(x '\right) = \ln x + 2$

Hence: $f \left(x\right)$ is $\ln x$ shifted +1 unit on the x axis and +2 units on the y axis. This is shown by the the grapg of $f \left(x\right)$ below:

graph{ln(x-1)+2 [-3.04, 16.96, -3.92, 6.08]}