Question

How do you graph `F(x)=ln(x-3)`?

Answer 1

y = F(x). Use the inverse relation `x = 3 + e^y. x>=3`. Graph meets x-axis at (4, 0). x =3 is the vertical asymptote, in the negative y-direction. Graph is from `(3+, -oo) to (oo, oo)` through (4, 0).

Explanation:

Plot points (3.25, ln 0.25), (3.5, ln 0.5), (4, 0), (4.5, ln 1.5), (5, ln 2),...to see how it rises from `(3+, -oo) to (oo, oo)`. through these points.