Question

How do you graph `f(x)=lnx-1`?

Answer 1

graph{lnx-1 [-10, 10, -5, 5]}
If you could draw the graph of `y=lnx`
Then it is very simple to draw the graph of `y=lnx+c`
Just the abscissa or the `x` axis will shift by `c` units downward if `c` is positive and upwards if `c` is negative keeping the graph of `y=lnx` at its own place and the new graph will correspond to `y= lnx+c`