# How do you graph f(x)=lnx-1?

If you could draw the graph of $y = \ln x$
Then it is very simple to draw the graph of $y = \ln x + c$
Just the abscissa or the $x$ axis will shift by $c$ units downward if $c$ is positive and upwards if $c$ is negative keeping the graph of $y = \ln x$ at its own place and the new graph will correspond to $y = \ln x + c$