Question

How do you graph `f(x) = log_(1/2) x+1`?

Answer 1

x > 0. x-intercept = 2. y-axis (`uarr`) is the asymptote. Ax `x to oo, y to -oo`. The inserted graph illustrates all these aspects.

Explanation:

`x > 0`.

`y = f(x) = log x/log(1/2)+1=-log x / log 2+1`
x-intercept ( y = 0 ) = 2. y-axis`uarr` is the asymptote ( `y.to oo` as `x to 0` ).

Ax `x to oo, y to -oo`.

The inserted graph illustrates all these aspects.

graph{(1-y)log 2-log x = 0 [-10.01, 10.01, -5, 5.01]}