# How do you graph f(x) = log_(1/2) x+1?

Dec 1, 2016

x > 0. x-intercept = 2. y-axis ($\uparrow$) is the asymptote. Ax $x \to \infty , y \to - \infty$. The inserted graph illustrates all these aspects.

#### Explanation:

$x > 0$.

$y = f \left(x\right) = \log \frac{x}{\log} \left(\frac{1}{2}\right) + 1 = - \log \frac{x}{\log} 2 + 1$
x-intercept ( y = 0 ) = 2. y-axis$\uparrow$ is the asymptote ( $y . \to \infty$ as $x \to 0$ ).

Ax $x \to \infty , y \to - \infty$.

The inserted graph illustrates all these aspects.

graph{(1-y)log 2-log x = 0 [-10.01, 10.01, -5, 5.01]}