How do you graph f(x)=log12x+1?

1 Answer
Dec 1, 2016

x > 0. x-intercept = 2. y-axis () is the asymptote. Ax x,y. The inserted graph illustrates all these aspects.

Explanation:

x>0.

y=f(x)=logxlog(12)+1=logxlog2+1
x-intercept ( y = 0 ) = 2. y-axis is the asymptote ( y. as x0 ).

Ax x,y.

The inserted graph illustrates all these aspects.

graph{(1-y)log 2-log x = 0 [-10.01, 10.01, -5, 5.01]}