How do you graph #g(x) = 1/4log_2 (x - 4) - 3#?

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Answer 1 · 2017-02-11T14:44:31

See graph and explanation.

To make g real, #x > 4#.

x-intercept ( y = 0 ) :4100, from, #log_2(x-4)=12#, giving x=4+2^12

Converting to ln,

g=1/4(ln(x-4)/ln 2)-3 and the Socratic graph is created.

Ax #x to oo, g to oo#.

Also, as #xto4, y to -oo#, revealing the asymptote x = 4..

x-intercept ( y = 8 ) :4100, from, #log_2(x-4)=12#, giving x=4+2^12

graph{(1/4ln(x-4)/ln2-3-y)=0 [0, 10000, -5, 5]}

The graph is no to uniform scale in both directions. Yet, it reveals features