Question

How do you graph, label the vertex, axis of symmetry and x intercepts of `y=-(x-2)(x+1)`?

Answer 1

The `x`-intercepts will be when `y=0`

Explanation:

This happens when `x=2orx=-1`, so the `x`-intercepts will be at `(-1,0)and(2,0)`

The axis of symmetry will be halfway between them, when
`x=(-1+2)/2=1/2`

The vertex will be on the axis of symmetry:
`x=1/2and y=-(1/2-2)(1/2+1)=2 1/4`
Or:
`(1/2,2 1/4)`
graph{-(x-2)(x+1) [-5.97, 8.08, -2.825, 4.2]}