How do you graph the circle with center at (-1, 2) and diameter 12?

1 Answer
Feb 24, 2016

Answer:

Draw a circle with center at #(-1, 2)# and radius of #6#. Equation of the circle is #x^2+y^2+2x-2y-31=0#

Explanation:

To graph the circle with center at #(-1, 2)# and diameter #12# means a radius of #12/2=6#, just draw a circle with center at #(-1, 2)# and radius of #12/2=6#.

As a point on circle is always a a distance of #6# from #(-1,2)#

#(x-(-1))^2+(y-2)^2=36# or #(x+1)^2+(y-2)^2=36# i.e.

#x^2+2x+1+y^2-2y+4=36# or

#x^2+y^2+2x-2y-31=0#

graph{x^2+y^2+2x-2y-31=0 [-15.8, 15.81, -7.9, 7.9]}