# How do you graph the ellipse #36x^2 + 9y^2 = 324#?

##### 1 Answer

#### Answer:

The most efficient way is to simplify the equation, find crucial points, and plot them on the graph.

#### Explanation:

For future reference: Formula for equation of vertical hyperbola

We need this equation in a more simplified form since the standard form must be equal to 1:

We can name some crucial values right from our equation. For instance, the center is

Let's graph this! We can set the center at

Vertices:

The covertices are

Covertices:

The foci are on the same line, the major axis, but are

Foci:

We can plot these points on a graph and try our best to draw a smooth line through the vertices and covertices. While the line doesn't pass through the foci, it's still an important part of the ellipse you need to know.

Here's a graph of the ellipse in case you're confused:

graph{x^2/9+y^2/36=1 [-20, 20, -10, 10]}