# How do you graph the equation 3x+y=-1?

Aug 21, 2017

Find values for $x$ and $y$ then plot the graph.

#### Explanation:

Start by separating $y$ on the left side of the equation. This gives you:

$y = - 3 x - 1$

Next set up plot points. Since this is a linear equation, you only need 2 points. Easy points are the $y$-intersect (the point where $x$ is $0$) and $1$.

The $y$-intersect is where $x$ is zero so using our equation:

$y = - 3 \left(0\right) - 1 \text{ }$ (substitute $0$ for the $x$ in the equation)

The $y$-intersect is $- 1$. The coordinate is $\left(0 , - 1\right)$.

You need one more point on the graph. We will use $x = 1$. Going back to our equation:

$y = - 3 \left(1\right) - 1 = - 4 \text{ }$ (substitute $1$ for $x$ in the equation)

This coordinate is $\left(1 , - 4\right)$.

With these two points, $\left(0 , - 1\right)$ and $\left(1 , - 4\right)$, you can plot your graph.

graph{(y+3x+1)((x-0)^2+(y+1)^2-0.06)((x-1)^2+(y+4)^2-0.06)=0 [-10, 10, -5, 5]}