How do you graph the equation #3x+y=-1#?

1 Answer

Find values for #x# and #y# then plot the graph.

Explanation:

Start by separating #y# on the left side of the equation. This gives you:

#y = -3x-1#

Next set up plot points. Since this is a linear equation, you only need 2 points. Easy points are the #y#-intersect (the point where #x# is #0#) and #1#.

The #y#-intersect is where #x# is zero so using our equation:

#y = -3(0) -1" "# (substitute #0# for the #x# in the equation)

The #y#-intersect is #-1#. The coordinate is #(0, -1)#.

You need one more point on the graph. We will use #x = 1#. Going back to our equation:

#y=-3(1) - 1 = -4" "# (substitute #1# for #x# in the equation)

This coordinate is #(1, -4)#.

With these two points, #(0, -1)# and #(1, -4)#, you can plot your graph.

graph{(y+3x+1)((x-0)^2+(y+1)^2-0.06)((x-1)^2+(y+4)^2-0.06)=0 [-10, 10, -5, 5]}