# How do you graph the equation by plotting points #3x + 5y = 12#?

##### 2 Answers

#### Answer:

First get the equation into standard form:

Then, start plugging in values for

#### Explanation:

**Getting the equation to standard form**

It will be *much* easier to plug in values if the equation is in standard form (so that

Next, divide each side by 5 to isolate

You can do the distributive property to get it to *truly* standard form, but it'll be pretty easier from here.

**Pluggin' in values**

I always find it helps to make a table, but however you want, find a way to record. Pick a simple value for

Work that out...

Try another! Let's have

Well,

graph{y = (-3x +12)/5 [-8.89, 8.89, -4.444, 4.445]}

#### Answer:

Express the equation in the point-slope form, i.e, y = mx + c.

#### Explanation:

Now put values of x in the equation and get corresponding values of y. Plot the graph according to the values you get.

For example :

when

when

when

graph{(-3/5)*x+12/5 [-7.174, 6.87, -1.386, 5.644]}