How do you graph the equation by plotting points #y = 2 sqrt (x) + 3#?

1 Answer
A. S. Adikesavan
Mar 11, 2016

#x >=0. and y>=3#. The graph is semi-parabola #(y-3)^2=4x#. It is upper half, including vertex at (0, 3). Passes through (0, 3), (9, 9), (16, 11),...#(n^2, 2n+3)#, ......

Explanation:

Indeed, interesting.
Axis of the parabola is y = 3. Focus is (1, 3).
Note that the mirror image about y = 3 is given by
#y=-2sqrtx+3#

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