# How do you graph the equation y<=2x+3?

Aug 9, 2017

First, find two points which solve the this if it is written as an equation and plot these two points on the grid then draw a line through the two points:

For $x = 0$:

$y = \left(2 \cdot 0\right) + 3$

$y = 0 + 3$

$y = 3$ or $\left(0 , 3\right)$

For $x = 2$:

$y = \left(2 \cdot 2\right) + 3$

$y = 4 + 3$

$y = 7$ or $\left(2 , 7\right)$

graph{(y - 2x - 3)(x^2 + (y-3)^2 - 0.125)((x - 2)^2 + (y - 7)^2 - 0.125) = 0 [-20, 20, -10, 10]}

Because the inequality is "less than or equal to" we can draw a solid line through the two points. And, also because it is "less than or equal to" we need to shade below the line.

graph{(y - 2x - 3) <= 0 [-20, 20, -10, 10]}