How do you graph the equation #y=3x-1.5#?

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Answer 1 · 2017-11-20T22:51:16

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = (3 xx 0) - 1.5#

#y = 0 - 1.5#

#y = -1.5# or #(0, -1.5)#

Second Point: For #x = 1#

#y = (3 xx 1) - 1.5#

#y = 3 - 1.5#

#y = 1.5# or #(1, 1.5)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+1.5)^2-0.025)((x-1)^2+(y-1.5)^2-0.025)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y-3x+1.5)(x^2+(y+1.5)^2-0.025)((x-1)^2+(y-1.5)^2-0.025)=0 [-10, 10, -5, 5]}