# How do you graph the equation #y=-3x+2#?

##### 1 Answer

#### Answer:

See below:

#### Explanation:

This equation is in slope-intercept form, which is my favourite for graphing lines.

The slope-intercept form is in the general form of:

where

Let's graph the

The

graph{(x-0)^2+(y-2)^2-.3^2=0}

So that's one point. Now let's plot another point (and then we can use a straightedge to join them).

The slope is

graph{((x-0)^2+(y-2)^2-.3^2)((x-1)^2+(y+1)^2-.3^2)=0}

And now connect them up!

graph{((x-0)^2+(y-2)^2-.3^2)((x-1)^2+(y+1)^2-.3^2)(y+3x-2)=0}