# How do you graph the equation y=-3x+2?

See below:

#### Explanation:

This equation is in slope-intercept form, which is my favourite for graphing lines.

The slope-intercept form is in the general form of:

$y = m x + b$

where $m$ is the slope and $b$ is the $y$-intercept.

Let's graph the $y$-intercept first.

The $y$-intercept is 2. This means that that point is $\left(0 , 2\right)$. So let's graph that:

graph{(x-0)^2+(y-2)^2-.3^2=0}

So that's one point. Now let's plot another point (and then we can use a straightedge to join them).

The slope is $- 3$. Slope is calculated by $\text{rise"/"run}$ - in other words the change in $y$ divided by the change in $x$. In this case, we will drop 3 spots for every 1 spot we move right. So that point is $\left(0 + 1 , 2 - 3\right) = \left(1 , - 1\right)$. Let's graph that:

graph{((x-0)^2+(y-2)^2-.3^2)((x-1)^2+(y+1)^2-.3^2)=0}

And now connect them up!

graph{((x-0)^2+(y-2)^2-.3^2)((x-1)^2+(y+1)^2-.3^2)(y+3x-2)=0}