Question

How do you graph the exponential function `f(x)=(1/2)^x -3`?

Answer 1

It has a vertical shift of -3. `(1/2)^X` will decrease over time, min of -3 (asymptote), y-int = -2

Explanation:

`(1/2)^x` has a minimum of zero (not including zero), as x approaches infinity, so 0-3 = -3 is a horizontal asymptote graph{(1/2)^x-3 [-10, 10, -5, 5]}

It has a y-intercept of -2 because 1-3 = -2
`(1/2)^0=1`