# How do you graph the exponential function f(x)=(1/2)^x -3?

Oct 6, 2016

It has a vertical shift of -3. ${\left(\frac{1}{2}\right)}^{X}$ will decrease over time, min of -3 (asymptote), y-int = -2

#### Explanation:

${\left(\frac{1}{2}\right)}^{x}$ has a minimum of zero (not including zero), as x approaches infinity, so 0-3 = -3 is a horizontal asymptote graph{(1/2)^x-3 [-10, 10, -5, 5]}

It has a y-intercept of -2 because 1-3 = -2
${\left(\frac{1}{2}\right)}^{0} = 1$