Question

How do you graph the exponential function `f(x) = 3^x+1`?

Answer 1

`f(x) > 1` for all `x in RR`; `f(0) = 2`; `lim_"x-> -oo" f(x) =1`
See graph below

Explanation:

`f(x) = 3^x+1`

Since `3^x >0` for all `x in RR`
`f(x) > 1` for all `x in RR`

`f(0) = 3^0+1 = 1+1 = 2`

`lim_"x-> -oo" f(x) = 0+1 =1`

graph{3^x+1 [-10, 10, -5, 5]}