# How do you graph the function, label the vertex, axis of symmetry, and x-intercepts. #y=x^2-2x+1#?

##### 1 Answer

**Vertex is at** **,axis of symmetry is**

**x intercept is** **,y intercept is** **additional
points on parabola are**

#### Explanation:

This is vertex form of equation ,

being vertex , here

Since

Therefore vertex is at

Axis of symmetry is

x-intercept is found by putting

x intercept is at

y-intercept is found by putting

y intercept is at

Additional points: Let

graph{x^2-2 x +1 [-10, 10, -5, 5]} [Ans]