Question

How do you graph the function, label the vertex, axis of symmetry, and x-intercepts. `y = 1/2x^2 + 6x`?

Answer 1

`y = x(x/2 + 6)`

x of vertex and axis of symmetry:

`x = -6/1 = -6`

y of vertex:`f(-6) = 36/2 - 36 = -18`

x- intercepts: `x = 0 and (x/2 + 6) = 0 -> x = -12`