How do you graph the function #y=5(2)^x#?

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Answer 1 · 2017-09-11T15:56:33

See below.

To find significant points notice that when #x = 0# we have #5(2)^0 => 5(1) = 5#

So y axis intercept is at #( 0 , 5 )#:

If #x < 0# we have #5/2^x#, as #x -> oo# , #5/2^x -> 0#

So the #x# axis is a horizontal asymptote.

if #x > 0 #

#5(2)^x -> oo#, as #x -> oo#

See graph:

graph{5(2)^x [-10, 10, -5, 50]}