# How do you graph the inequality 15>3z?

Aug 22, 2017

See a solution process below:

#### Explanation:

First, we need to get the inequality in terms of $z$. Divide each side of the inequality by $\textcolor{red}{3}$ to solve for $z$ while keeping the inequality balanced:

$\frac{15}{\textcolor{red}{3}} > \frac{3 z}{\textcolor{red}{3}}$

$5 > \frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{3}}} z}{\cancel{\textcolor{red}{3}}}$

$5 > z$

Or, we can reverse or "flip" the inequality to state the solution in terms of $z$:

$z < 5$

To graph this we draw a vertical line at the point $5$ on the horizontal axis.

The line will be a dashed line because the there is no "or equal to" clause in the inequality operator so the value $5$ is not included in the solution set.

We we shade to the left of the line because the inequality operator is a "less than" clause.

graph{x<5}