How do you graph the inequality -3x+2y>3, x+4y< -2?

Apr 7, 2016

Solve system of linear inequalities

Explanation:

Bring the inequalities to standard forms:
- 3x + 2y - 3 > 0 (1)
x + 4y + 2 < 0 (2)
First, graph line (1) --> -3x + 2y - 3 = 0 by its two intercepts.
Make x = o--> y-intercept y = 3/2
Make y = 0, x-intercept --> x = -1
Next, graph Line (2) --> x + 4y + 2 = 0 by its 2 intercept.
Make x = 0, y-intercept y = -1/2.
Make y= 0, x-intercept --> x = -2.
The solution set of inequality (1) is the area above Line (1).
The solution set of inequality (2) is the area below the Line (2).
The common solution set is the area commonly shared by the
2 solution sets.
graph{-3x + 2y - 3 = 0 [-10, 10, -5, 5]}
graph{x + 4y + 2 = 0 [-10, 10, -5, 5]}