How do you graph the inequality 3x-4y<= 16?

Draw the straight line $3 x - 4 y = 16$. Including the line shade the region above this lin, in the positive y-direction Enter therein $3 x - 4 y \le 16$
Rearranging, $y \ge \left(\frac{3}{4}\right) x - 4$.
Draw the straight line $y = \left(\frac{3}{4}\right) x - 4$.. On this line and above, in the
positive y-direction, $y \ge \left(\frac{3}{4}\right) x - 4$, and so, $3 x - 4 y \le 16$.