# How do you graph the inequality # 4x+3y> -12#?

##### 1 Answer

See a solution process below:

#### Explanation:

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.

**For:**

**For:**

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.

The boundary line will be solid because the inequality operator contains an "or equal to" clause.

graph{(x^2+(y+4)^2-0.05)((x+3)^2+y^2-0.05)(4x+3y+12)=0 [-15, 15, -7.5, 7.5]}

Now, we can shade the right side of the line. We also have to make the boundary line a dashed line because the inequality operator does not contain an **"or equal to"** clause so the boundary line is not included in the solution set.

graph{(4x+3y+12) > 0 [-15, 15, -7.5, 7.5]}