How do you graph the inequality #6x + 4y ≤ 24#?
1 Answer
See a solution process below:
Explanation:
First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.
For:
For:
We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.
The boundary line will be solid because the inequality operator contains an "or equal to" clause.
graph{(x^2+(y-6)^2-0.125)((x-4)^2+y^2-0.125)(6x+4y-24)=0 [-20, 20, -10, 10]}
Now, we can shade the left side of the line.
graph{(6x+4y-24) <= 0 [-20, 20, -10, 10]}