# How do you graph the inequality #x + 2y < 3#, #2x – 3y<6#?

##### 1 Answer

Jul 3, 2016

The lines meet at (3, 0) and the y-intercepts are

Shade the region on the left of (3, 0), in-between the lines. For any point (x, y) here, both the inequalities are satisfied.

#### Explanation:

Rearrange to the forms

Now, the line

line #y+2/3x-2 cuts the axes at (3, 0) and (0, -2). (3, 9) is the common

point. For any point (x, y) in the region enclosed by these lines, on

the left of the common point (3,

Separately, this is the given pair of inequalities.

The opposite region, on the right of (3, 0), is for the reversed inequalities.