How do you graph the inequality #x + 2y < 3#, #2x – 3y<6#?
The lines meet at (3, 0) and the y-intercepts are
Shade the region on the left of (3, 0), in-between the lines. For any point (x, y) here, both the inequalities are satisfied.
Rearrange to the forms
Now, the line
line #y+2/3x-2 cuts the axes at (3, 0) and (0, -2). (3, 9) is the common
point. For any point (x, y) in the region enclosed by these lines, on
the left of the common point (3,
Separately, this is the given pair of inequalities.
The opposite region, on the right of (3, 0), is for the reversed inequalities.