# How do you graph the inequality x+5y<=7?

Draw the straight line $y = \frac{7 - x}{5}$ that passes through (7, 0) and (0, 7/5). Shade the region below this line (including this line) in the negative y-directions, Enter therein $x + 5 y \le 7$.
The inequality is equivalent to $y \le \frac{7 - x}{5}$.
Draw the straight line $y = \frac{7 - x}{5}$ that passes through $\left(7 , 0\right) \mathmr{and} \left(0 , \frac{7}{5}\right)$.
For any point (x, y) on this line or below this line, $y \le \frac{7 - x}{5}$, and so, $x + 5 y \le 7$.