# How do you graph the inequality x+y>1?

Mar 14, 2018

See a solution process below:

#### Explanation:

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.

For: $x = 0$

$0 + y = 1$

$y = 1$ or $\left(0 , 1\right)$

For: $y = 0$

$x + 0 = 1$

$x = 1$ or $\left(1 , 0\right)$

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.
The boundary line will be solid because the inequality operator contains an "or equal to" clause.

graph{(x^2+(y-1)^2-0.05)((x-1)^2+y^2-0.05)(x+y-1)=0 [-10, 10, -5, 5]}

Now, we can shade the rightside of the line.

The boundary line will be changed to a dashed line because the inequality operator does not contain an "or equal to" clause.

graph{(x+y-1) > 0 [-10, 10, -5, 5]}