How do you graph the inequality #y< -2/3x+1 #, #y>4x-5#?

1 Answer
Dec 24, 2016

Any (x, y) in the shaded region on the LHS of the common point #(9/7, 1/7)#, sans the common point and the dotted lines, is a solution to the combined inequality..

Explanation:

The shaded region in the graph represents

#{y<-2/3x+1 and y > 4x-5}# and the reversed-opposite

#{y>-2/3x+1 and y < 4x-5}#.

Our solutions (x, y) are in the LHS of the common point #(9/7, 1/7)#,

sans the common point and the dotted lines..

Please ignore the part on the RHS.

graph{(y+2/3x-1)(y-4x+5)<0x^2 [-10, 10, -5, 5]}