# How do you graph the inequality y<2/3x + 3?

The slope is $\left(\frac{2}{3}\right)$ and the y-intercept is $3$
The inequality is already written in the slope/intercept form, y=mx+b, where $m$ is the slope of the line and $b$ is the y-intecept. Since you are dealing with the inequality $<$, the graph is everything below and not including the line $y = \left(\frac{2}{3}\right) x + 3$. Therefore shade the region below the broken line, which shows that the line is not included in the solution.