# How do you graph the inequality y>(x-3)^2-4?

Plot $y = {\left(x - 3\right)}^{2} - 4 :$
Vertex is $\left(3 , - 4\right)$, and passes through $\left(1 , 0\right) , \left(5 , 0\right)$
It is a parabola, opened upwared. $y > {\left(x - 3\right)}^{2} - 4$ happens inside the shape.